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Q. During the thermodynamic process shown in figure for an ideal gasPhysics Question Image

Thermodynamics

Solution:

image
For a straight $P-V$ graph line $P \propto V$
If pressure increases, volume increases then $T$ also increases $[P V \propto T]$
So $\Delta T \neq 0$
Volume increasing so work is positive, $W>0$
and temperature also increasing so $\Delta Q>0$
$\because \Delta Q=\Delta U+\Delta W$
So $\Delta U>0$