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Q. During the electrolysis of molten sodium chloride, the time required to produce $0.10$ mol of chlorine gas using a current of $3$ amperes is

NEETNEET 2016Electrochemistry

Solution:

At Cathode:
$2H_2O \xrightarrow{2e^{-}} H_2 + 2OH^{-}$
At anode:
$2Cl^{-} \xrightarrow{2e^{-}} Cl_2 + 2e^{-}$
$\frac{W}{E} = \frac{It}{96500}$
$0.1 \times 2 = \frac{3 \times t(sec)}{96500}$
$t = 6433\, \sec$
$t = 107.2\, \min$
$\sim 110 \min$.