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Q. During the adiabatic expansion of $2 \, \text{m}\text{o}\text{l}$ of an ideal gas, the increase in internal energy was found to be equal to $\left(\right.-200 \, \text{J}\left.\right)$ . The work done by the gas during the process will be equal to

NTA AbhyasNTA Abhyas 2022

Solution:

According to first law of thermodynamics,
$\Delta Q=\Delta U+\Delta W$ ...(i)
Given, $\Delta U=-200 \, \text{J}$
$\Delta Q=0$ (due to adiabatic process)
Substituting in Equation (i), we get
$0=-200+\Delta W$
$\Longrightarrow \Delta W=200 \, \text{J}$