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Q.
During electrolysis of a solution of $AgNO_3$, $9650$ coulombs of charge is passed through the solution. What will be the mass of silver deposited on the cathode?
Electrochemistry
Solution:
$Ag^+ + \underset{\text{1F}}{e^-} \to \underset{\text{108 g}}{Ag}$
Amount of Ag deposited by $9650 \,C$
$=\frac{108}{96500}\times9650$
$=10.8\,g$