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Q.
Drops of liquid of density $d$ are floating half immersed in a liquid of density $\rho$. If the surface tension of the liquid is $T$, then the radius of the drop is
EAMCETEAMCET 2012
Solution:
According to the question,
or $\frac{4}{3} \pi r^{3} d g =\frac{2}{3} \pi r^{3} \rho g+T \times 2 \pi r $
$r =\sqrt{\frac{3 T}{g(2 d-\rho)}}$