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Physics
Diwali rocket is ejecting 50 g of gasses at a velocity of 400 m/s . The accelerating force on the rocket will be
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Q. Diwali rocket is ejecting $50\, g$ of gasses at a velocity of $400 \,m/s$ . The accelerating force on the rocket will be
JIPMER
JIPMER 2009
Motion in a Straight Line
A
22 dyne
B
20 N
C
20 dyne
D
100 N
Solution:
The accelerating force on the rocket
upward thrust $=\frac{\Delta m}{\Delta t} \cdot u$
Given, $\frac{\Delta m}{\Delta t}=50 \times 10^{-3} kg / s ,\, v=400\, m / s$
So, accelerating force $=50 \times 10^{-3} \times 400$
$=20\, N$