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Q. Distance of 5th dark fringe from centre is 4 mm. If D = 2 m, $\lambda$ = 600 nm, then distance between slits is :

AIIMSAIIMS 2019

Solution:

Distance of 5th dark
Fringe from centre = $\frac{9\beta}{2}$
$\frac{9\times\lambda\times D}{2\times d}=4\times10^{-3}\quad\Rightarrow \quad\quad d=\frac{9\times6\times10^{-7}\times2}{2\times4\times10^{-3}}=1.35$ mm