1. Tardigrade
  2. Question
  3. Chemistry
  4. Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Dissolving $120 \,g$ of urea (mol. wt. $60$) in $1000 \,g$ of water gave a solution of density $1.15\, g/mL$. The molarity of the solution is

IIT JEEIIT JEE 2011Some Basic Concepts of Chemistry

Solution:

Molarity $=\frac{\text { Moles of solute }}{\text { Volume of solution (L) }}$
Moles of urea $=\frac{120}{60}=2$
Weight of solution $=$ Weight of solvent $+$ Weight of solute
$=1000+120=1120 \,g$
$\Rightarrow $ Volume $=\frac{1120 \,g }{1.15\, g / mL } \times \frac{1}{1000 \,mL / L }=0.973 \,L$
$\Rightarrow $ Molarity $=\frac{2.000}{0.973}=2.05 \,M$