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  4. Dissolving 120 g of a compound (mol. wt = 60) in 1000 g of water gave a solution of density 1.12 g mL-1. The molarity of solution is

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Q. Dissolving $120\, g$ of a compound (mol. wt $= 60$) in $1000\, g$ of water gave a solution of density $1.12\, g \, mL^{-1}$. The molarity of solution is

AP EAMCETAP EAMCET 2018

Solution:

Given, density $(d)=1.12\, g\, mL ^{-1}$

Mass of solute $(w)-120\, g$

Molar mass of solute $(M)=60$

Mass of solvent $(w)=1000\, g =1000\, mL$

$\therefore $ Total mass $=1000+120=1120\, g$

$\because d=\frac{\text { Mass }}{\text{Volume}(V)}$

$\therefore $ Total volume $(V)=\frac{1120}{1.12}=1000\, mL$

$\because$ Molarity $(c)=\frac{w}{M} \times \frac{1000}{V}$

$\because$ Molarity $(c)=\frac{w}{m} \times \frac{1000}{1000}=\frac{120}{60}=2.0\, m$