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  3. Chemistry
  4. Disintegration constant for a radioactive substance is 0.58 per hour. Its half-life period is:

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Q. Disintegration constant for a radioactive substance is $0.58$ per hour. Its half-life period is:

BHUBHU 2004

Solution:

$t_{1 / 2}=0.693 / \lambda$
Given, $\lambda=0.58 h ^{-1},$
$ \lambda=?$
$t_{1 / 2} =\frac{0.693}{0.58}$
$=1.19\, h $
$=1.2\, h$