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Chemistry
Dipole moment of CH3CH2CH3 (I), CH3CH2OH (II) and CH3CH2F (III) is in order
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Q. Dipole moment of $CH_{3}CH_{2}CH_{3} (I)$, $CH_{3}CH_{2}OH (II)$ and $CH_{3}CH_{2}F (III)$ is in order
Alcohols Phenols and Ethers
A
$I <\,II<\,III$
33%
B
$I >\,II>\,III$
28%
C
$I<\,III<\,II$
24%
D
$III<\,I<\,II$
15%
Solution:
Higher the electronegativity between C-X, higher will be the dipole moment