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Q. Dimensions of Planck's constant are

J & K CETJ & K CET 2015

Solution:

Energy $[E]=$ Planck's constant $[A] \times$ Frequency $[v]$
$\Rightarrow E=h v$
$\Rightarrow [E]=[h][v]$
$\Rightarrow \left[M L^{2} T^{-2}\right]=[h]\left[\frac{1}{T}\right]$
$\Rightarrow [h]=\left[M L^{2} T^{-2}\right][T]$
$\therefore $ Dimension of $h=[h]=\left[M L^{2} T^{-1}\right]$