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Q. Dimensions of 'ohm' are same as (where $\mathrm{h}$ is planck's constant and e is charge):

Physical World, Units and Measurements

Solution:

$\text { } \frac{\mathrm{h}}{\mathrm{e}^{2}}=\frac{\mathrm{ML}^{2} \mathrm{~T}^{-1}}{(\mathrm{AT})^{2}}=\mathrm{ML}^{2} \mathrm{~T}^{-3} \mathrm{~A}^{-2}=\text {Resistance }(\mathrm{ohm})$