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Q. Dimensions of $\frac{1}{\mu_{0}\varepsilon_{0}}$, where symbols have their usual meaning, are

Physical World, Units and Measurements

Solution:

Velocity is given by
$v=\frac{1}{\sqrt{\mu_{0}\varepsilon_{0}}}$
$\therefore v^{2}=\frac{1}{\mu_{0}\varepsilon_{0}}=\left[LT^{-1}\right]^{2}$
$\therefore \frac{1}{\mu_{0}\varepsilon_{0}}=\left[L^2T^{-2}\right]$