Among group- $13$ elements $(B,\, Al,\, Ga)$ and titanium $(Ti)$, boron $(B)$ does not react with dilute $NaOH$, but $B$ reacts with concentrated $NaOH$.
$B+\underset{\text { Conc. }}{ NaOH }+3 H _{2} O \rightarrow Na \left[ B ( OH )_{4}\right]+\frac{3}{2} H _{2}$