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Q. Different words are being formed by arranging the letters of word 'SUCCESS'.
The number of words in which the consonants appear in alphabetical order is

Permutations and Combinations

Solution:

Since, the consonants have to appear in alphabetical order, we have
$XCXCXSXSXSX$
Case I $U$ and $E$ are together
Number of words $={ }^6 C_1 \times 2 !=12$
Case II $U$ and $E$ are separated.
Number of words $={ }^6 C_2 \times 2 !=\frac{6 \times 5}{2 \times 1} \times 2=30$
$\therefore$ Required number of words $=30+12=42$