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Q. Diborane does not undergo cleavage reaction with

The p-Block Elements

Solution:

$B_{2}H_{6}$ forms addition product with $(CH_{3})_{3}N$, $NH_{3}$ and $CO$ as:
$B_{2}H_{6} + 2N(CH_{3})_{3} \to [2H_{3}B \leftarrow N(CH_{3})_{3}]$
$B_{2}H_{6} + 2NH_{3} \to [BH_{2}(NH_{3})_{2}]^{+} [BH_{4}]^{-}$
$B_{2}H_{6} + 2CO \to 2[BH_{3}. CO]$