Question

Deuteron and $\alpha$ - particle are put $1 \,\mathring{A}$ apart in air. Magnitude of intensity of electric field due to deuteron of $\alpha$ - particle is

• A. zero
• B. $ 2.88\times {{10}^{11}}\,N/C $
• C. $ 1.44\times {{10}^{11}}\,N/C $
• D. $ 5.76\times {{10}^{11}}\,N/C $

Answer 1

Answer: (C)

$E=9 \times 10^{9} \times \frac{q}{n}$
$=9 \times 10^{9} \frac{1.6 \times 10^{-19}}{\left(1 \times 10^{-10}\right)^{2}} $
$=1.44 \times 10^{11} \,M / C$