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Q. Deuterium was discovered in $1932$ by Harold Urey by measuring the small change in wavelength for a particular transition in $^{1}H$ and $^{2}H$. This is because, the wavelength of transition depend to a certain extent on the nuclear mass. If nuclear motion is taken into account then the electrons and nucleus revolve around their common centre of mass. Such a system is equivalent to a single particle with a reduced mass $\mu$, revolving around the nucleus at a distance equal to the electron-nucleus separation.
Here $\mu = m_eM/(m_e + M)$ where $M$ is the nuclear mass and $m_e$ is the electronic mass. Estimate the percentage difference in wavelength for the 1st line of the Lyman series in $^{1}H$ and $^{2}H$.
(Mass of $^{1}H$ nucleus is $1.6725 \times 10^{-27}\, kg$, Mass of $^{2}H$ nucleus is $3.3374 \times 10^{-27}\, kg$, Mass of electron $= 9.109 \times 10^{-31}\, kg$.)

Atoms

Solution:

Correct answer is (b) $2.7\times 10^{-2} \%$