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Q. Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is:

AIEEEAIEEE 2006Some Basic Concepts of Chemistry

Solution:

molality (m) $= \frac{M}{1000 \,d -MM_{1}}\times100$
M = Molarity
$M_{1}$ = Molecular mass
d = density
$= \frac{2.05}{\left(1000\times1.02\right)-\left(2.05\times60\right)}\times1000$
$= 2.28 \,mol \,kg^{-1}$