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  4. Density of a 2.05 M solution of acetic acid in water is 1.02 g / mL. The molality of the solution is

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Q. Density of a $2.05\, M$ solution of acetic acid in water is $1.02\, g / mL$. The molality of the solution is

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Solution:

Molality $, m=\frac{M}{1000\, d-M M_{2}} \times 1000$

where, $M=$ molarity, $d=$ density, $M_{2}=$ molecular mass

$m=\frac{2.05}{1000 \times 1.02-2.05 \times 60}=\frac{2.05}{897}$

$=2.28 \times 10^{-3} mol \,g ^{-1}=2.28\, mol\, kg ^{-1}$