Tardigrade
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Tardigrade
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Chemistry
Δ Hsolution of anhydrous CuSO4 is -15.9 kcal/mol and heat of hydrate of CuSO4(s) into CuSO4.5H2O(s) is -18.9 kcal/mol. The heat of solution of CuSO4.5H2O is
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Q. $\Delta H_{solution}$ of anhydrous $CuSO_4$ is $-15.9$ kcal/mol and heat of hydrate of $CuSO_4(s)$ into $CuSO_4.5H_2O(s)$ is $-18.9$ kcal/mol. The heat of solution of $CuSO_4.5H_2O$ is
A
-3.0 kcal/mol
B
+3.0 kcal/mol
C
-34.8 kcal/mol
D
+34.8 kcal/mol
Solution:
Correct answer is (b) +3.0 kcal/mol