Question

$\Delta G^{o}$ of the cell reaction
$AgCl (s) + \frac{1}{2} H_{2} (g) = Ag (s) + H^{+} + Cl^{-} is -21.52 kJ.$
$\Delta G^{o}$ of $2AgCl (s) + H_{2} (g)$ = $2Ag (s) + 2H^{+} + 2Cl^{-}$ is

• A. $-21.52\, kJ$
• B. $-10.76\, kJ$
• C. $-43.04\, kJ$
• D. $43.04\, kJ$

Answer 1

Answer: (C)

$K_{C_2}=K_{C_1}^{2}$
$\therefore \Delta G=-nfE_{o}=-RT ln K_{c}$
$\therefore G_{2} =2\times\left(-21.52\right)=-43.04 KJ $