Question

Daniell cell is shown as

• A. $Zn _{(s)} |Zn ^{2+}{ }_{(a q)} \| Cu _{(s)} \mid Cu ^{2+}_{(a q)}$
• B. $Zn _{(a q)}^{2+}\left| Zn _{(s)} \| Cu _{(s)}\right| Cu ^{2+}(a q)$
• C. $Zn _{(s)}\left| Zn ^{2+}{ }_{(a q)} \| Cu ^{2+}(a q)\right| Cu _{(s)}$
• D. $Zn _{(s)}\left| Cu ^{2+}{ }_{(a q)} \| Zn ^{2+}{ }_{(a q)}\right| Cu _{(s)}$

Answer 1

Answer: (C)

The overall reaction of Daniell cell is

$Zn _{(s)}+ Cu ^{2+}{ }_{(a q)} \rightarrow Cu _{(s)}+ Zn ^{2+}_{(aq)}$

So, its cell representation will be as follows:

$Zn _{(s)}\left| Zn ^{2+}{ }_{(a q)} \| Cu ^{2+}{ }_{(a q)}\right| Cu _{(s)}$