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  4. (d/d x)(3 cos ((π/6)+x°)-4 cos 3((π/6)+x°))=

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Q. $\frac{d}{d x}\left(3 \cos \left(\frac{\pi}{6}+x^{\circ}\right)-4 \cos ^{3}\left(\frac{\pi}{6}+x^{\circ}\right)\right)=$ _______

Gujarat CETGujarat CET 2019

Solution:

$\frac{d}{d x}\left(-\cos 3\left(\frac{\pi}{6}+x^{\circ}\right)\right)=\frac{d}{d x}\left(-\cos \left(\frac{\pi}{2}+3 x^{\circ}\right)\right)=$
$\frac{d}{d x}\left(\sin 3 x \frac{\pi}{180}\right)=\frac{3 \pi}{180} \cos 3 x^{\circ}$