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Q. Cyclopropane rearranges to form propene
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This follows first order kinetics. The rate constant is $2.714\times10^{-3}$ $sec^{-1}$. The initial concentration of cyclopropane is $0.29$ $M^{\cdot}.$ What will be the concentration of cyclopropane after $100$ sec?

Chemical Kinetics

Solution:

$k=\frac{2.303}{t} log$ $\frac{a}{\left(a-x\right)}$
$\left(a-x\right)$ is the concentration left after $100$ sec.
$2.7\times10^{-3}$ $=\frac{2.303}{100}log$ $\frac{0.29}{\left(a-x\right)}$
$\Rightarrow $ $\frac{0.27}{2.303}=log$ $\frac{0.29}{\left(a-x\right)}$
$\Rightarrow $ $0.117=log$ $\frac{0.29}{\left(a-x\right)}$
$\Rightarrow $ $\left(a-x\right)=0.22 M$