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Chemistry
CuSO4 reacts with excess KCN to form
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Q. $CuSO_{4}$ reacts with excess $KCN$ to form
NTA Abhyas
NTA Abhyas 2022
A
$Cu\left(\right.CN\left(\left.\right)_{2}$
B
$Cu\left(\right.NCN\left(\left.\right)_{2}$
C
$K_{2}\left[\right.Cu\left(\right.CN\left(\left.\right)_{4}\left]\right.$
D
$K_{3}\left[\right.Cu\left(\right.CN\left(\left.\right)_{4}\left]\right.$
Solution:
$CuSO_{4}+2KCN \rightarrow Cu\left(\right.CN\left(\left.\right)_{2}+K_{2}SO_{4}$
$2Cu\left(\right.CN\left(\left.\right)_{2} \rightarrow Cu_{2}\left(\right.CN\left(\left.\right)_{2}+\left(\right.CN\left(\left.\right)_{2}$
$Cu_{2}\left(\right.CN\left(\left.\right)_{2}+KCN\left(\right.excess\left.\right) \rightarrow K_{3}\left[\right.Cu\left(\right.CN\left(\left.\right)_{4}\left]\right.$