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Q.
$ \text{CuS}{{\text{O}}_{\text{4}}} $ reacts with $ \text{N}{{\text{H}}_{\text{4}}}\text{OH} $ to give deep blue complex of:
VMMC MedicalVMMC Medical 2002
Solution:
When $ \text{CuS}{{\text{O}}_{\text{4}}} $ reacts with $ \text{N}{{\text{H}}_{\text{4}}}\text{OH,} $ deep blue colour is formed due to the formation of cupra ammonium sulphate. $ \underset{\text{Copper}\,\text{sulphate}}{\mathop{\text{CuS}{{\text{O}}_{4}}}}\,+\underset{\left( \begin{smallmatrix} \text{ammonium} \\ \text{hydroxide} \end{smallmatrix} \right)}{\mathop{N{{H}_{4}}OH}}\,\xrightarrow{{}}\underset{\begin{smallmatrix} \text{Cupra}\,\text{ammonium} \\ \text{sulphate} \end{smallmatrix}}{\mathop{[Cu{{(N{{H}_{3}})}_{4}}]S{{O}_{4}}}}\, $