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Q. Current in an inductance of 1 mH is reduced from 5A to 0 in 1 ms. The emf induced in it is (in V)

KCETKCET 1998Electromagnetic Induction

Solution:

E = $\frac{Ld I}{dt} = 10^{-3} \frac{5}{10^{-3}}$ = 5V