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Q. Current flows through a metallic conductor whose area of cross-section increases in the direction of the current. If we move in this direction.

Current Electricity

Solution:

$I=n e A v_{d} \Rightarrow v_{d}=\frac{I}{n e A}$
$v_{d} \propto \frac{I}{A} ;$ so as $A$ increases $v_{d}$ decreases