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Chemistry
[Cu (NH3)4]2+ shows the following hybridization
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Q. $ [Cu (NH_3)_4]^{2+} $ shows the following hybridization
MHT CET
MHT CET 2012
A
$ dsp^2 $
B
$ sp^3d $
C
$ dsp^3 $
D
$ sp^3 $
Solution:
$_{29} Cu =[ Ar ] 3 d ^{10} 4 s^{1} $
$Cu ^{2+} =[ Ar ] 3 d^{9} $
$Cu ^{2+}=$ Ground state
$\left[ Cu \left( NH _{3}\right)_{4}\right]^{2+}=$