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  4. CsBr has bcc structure with edge length 4.3 mathringA The shortest inter ionic distance in between Cs+ and Br- is

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Q. $CsBr$ has $bcc$ structure with edge length $4.3\,\mathring{A}$ The shortest inter ionic distance in between $Cs^+$ and $Br^-$ is

The Solid State

Solution:

For bcc structure, atomic radius, $r = \frac{\sqrt{3}}{4} a $
$ = \frac{\sqrt{3}}{4} \times 4.3 = 1.86$
Since, r = half the distance between two nearest neighbouring atoms.
$\therefore $ Shortest inter ionic distance = 2 $\times $ 1.86
= 3.72