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  4. Crystal field stabilization energy for high spin d4 octahedral complex is

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Q. Crystal field stabilization energy for high spin $d^{4}$ octahedral complex is

NTA AbhyasNTA Abhyas 2022

Solution:

For high spin $d^{4}$ Octahedral complex the splitting is given by
$\text{CFSE} \, \text{=} \, \left[- \text{0} 4\times \, \text{3} \, \text{+} \, \text{0} \text{.6} \, \times \, \text{1}\right]\text{Δ}_{\text{0}}$
$= \left[- 1.2 + 0.6\right] \text{Δ}_{\text{0}}$
$= - 0.6 \, \text{Δ}_{\text{0}}$