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Q. Critical angle of glass is $\theta_1$ and that of water is $\theta_2$ The critical angle for water and glass surface would be $(\mu_g = 3/2, \mu_w = 4/3)$.

Ray Optics and Optical Instruments

Solution:

As $^{w}\mu_{g} = 9/8 < ^{a}\mu_{w} < ^{a}\mu_{g} $
$ \therefore \theta > \theta_{2} > \theta_{1}$