Question

$\left[ Cr \left( H _{2} O \right)_{6}\right] Cl _{3}$ (atomic number of $Cr =24$ ) has a magnetic moment of $3.83 BM$. The correct distribution of $3 d$-elections in the chromium present in the complex is

• A. $3d^{1}_{xy},3d^{1}_{yz},3d^{1}_{zx}$
• B. $3d^{1}_{xy},3d^{1}_{yz},3d^{1}_{z^{2}}$
• C. $3d^{1}_{_{\left(x^{2}y^{2}\right)}}3d^{1}_{_{z^{2}}}3d^{1}_{zx}$
• D. $3d^{1}_{xy},3d^{1}_{_{\left(x^{2}y^{2}\right)}},3d^{1}_{xz}$

Answer 1

Answer: (A)

Magnetic moment indicates that there are three unpaired electrons present in chromium. These must be present in lower energy orbitals which are $3d^{1}_{ xy},\,3d^{1}_{ yz}$ and $3d^{1}_{ xz}.$