Question

$[Cr(H_{2}O)_{6}]Cl_{3}$ has a magnetic moment of $3.83\, B.M$. The correct distribution of $3d$ electrons in the chromium of the complex is

• A. $3dxy^{1} ,3dyz^{1}, 3dz^{2}$
• B. $3d^{1}xy, 3d^{1}yz, 3d^{1}zx$
• C. $3d_{\left(x^{2}-Y^{2}\right)^{1,}} 3d^{1}z^{2},3d^{1} xz$
• D. $3dxy^{1}, 3d^{1}x^{2}-y^{2}, 3d^{1}y^{2}$

Answer 1

Answer: (B)

$3.83 =\sqrt{n\left(n+2\right)} so, n=3$
So, these are three unpaired $e^{-}s$. Based on crystal field splitting the orbital of $t_{2g}$ set have one $e^{-}$ each.