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Q.
Covalency and oxidation numbers of nitrogen in $N_2O_5$ is respectively
The p-Block Elements - Part2
Solution:
Covalency of $N$ is $4$ in $N_2O_5$ and its oxidation state is $+5$.
As clear from the structure of $N _{2} O _{5}$, covalency of nitrogen is $4$ but the oxidation state is $+5$.
$x-2$
$N _{2} O _{5}$ is a neutral compound. Let the oxidation state of $N _{2} O _{5}$ be $x$.
$(2 \times x)+(-2 \times 5)=0 $
$2 x-10=10 $
$x=5$
