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Q. $\cot^{-1} \left(\cot \frac{5\pi}{6}\right)= $

Inverse Trigonometric Functions

Solution:

$\cot^{-1} \left(\cot \frac{5\pi}{6}\right)= \frac{5\pi}{6} \left(\because \frac{ 5\pi}{6} \in\left(0, \pi\right)\right)$