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Q. $cot^{-1}\left(\frac{ab + 1}{a - b}\right)+cot^{-1}\left(\frac{bc + 1}{b - c}\right)+cot^{-1}\left(\frac{ca + 1}{c- a}\right)$

Inverse Trigonometric Functions

Solution:

$cot^{-1}\left(\frac{ab + 1}{a - b}\right)+cot^{-1}\left(\frac{bc + 1}{b - c}\right)+cot^{-1}\left(\frac{ac + 1}{c- a}\right)$
$\Rightarrow cot^{-1} a - cot^{-1} b + cot^{-1} b- cot^{-1} c + cot^{-1}c - cot^{-1} a = \pi$