1. Tardigrade
  2. Question
  3. Mathematics
  4. cos 50° 50 prime cos 9° 10 prime- sin 50° 50 prime sin 9° 10 prime=

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $\cos 50^{\circ} 50^{\prime} \cos 9^{\circ} 10^{\prime}-\sin 50^{\circ} 50^{\prime} \sin 9^{\circ} 10^{\prime}=$

Trigonometry

Solution:

Use $\cos A \cos B-\sin A \sin B=\cos (A+B)$.