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  4. Correct graphical representation of Boyle’s law is

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Q. Correct graphical representation of Boyle’s law is

Solution:

$\left(i\right) T_{1} < T_{2} < T_{3}$ (correct)
$ \left(ii\right) T_{3} < T_{2} < T_{1}$ correct
$\left(iii\right) P = \frac{K}{V} $
$ \begin{matrix}log P&= &-log V&+log K\\ \ce{v}&&\ce{v}&\ce{v}\\ y&=&\left(-1\right)x&+c\end{matrix}$