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Chemistry
Correct formula of the complex formed in the brown ring test for nitrates is
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Q. Correct formula of the complex formed in the brown ring test for nitrates is
Coordination Compounds
A
$\left[ Fe \left( H _{2} O \right)_{4}( NO )_{2}\right]$
9%
B
$\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{2+}$
60%
C
$\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{+}$
22%
D
$\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{3+}$
10%
Solution:
Complex formed in brown ring test for nitrates is $\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{2^{+}}$