Question

Correct formula of the complex formed in the brown ring test for nitrates is

• A. $FeSO _{4} NO$
• B. $\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{2+}$
• C. $\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{+}$
• D. $\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{3+}$

Answer 1

Answer: (B)

The correct formula of the complex formed in the brown ring test for nitrates is:
$\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{2+}$
It is formed through the following reaction:
$FeSO _{4}+5 H _{2} O + NO \rightarrow\left[ Fe \left( H _{2} O \right)_{5} NO \right] SO _{4}$