Question

Copper has face centered cubic (fcc) lattice with interatomic spacing equals to $ 2.54\text{ }\overset{o}{\mathop{\text{A}}}\, $ . The value of lattice constant for this lattice is

• A. $ \text{3}\text{.59}\overset{o}{\mathop{\text{A}}}\, $
• B. $ 2.54\overset{o}{\mathop{\text{A}}}\, $
• C. $ 1.27\overset{o}{\mathop{\text{A}}}\, $
• D. $ 5.08\overset{o}{\mathop{\text{A}}}\, $

Answer 1

Answer: (A)

The value of lattice constant $ a=\frac{4r}{\sqrt{2}} $ $ =2\sqrt{2}\times r $ $ =2\sqrt{2}\times 2.54/2 $ $ =3.59A $