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Q. Coolant used in car radiator is aqueous solution of ethylene glycol. In order to prevent the solution from freezing at $-0.3^{\circ} C$. How much ethylene glycol must be added to $5\, kg$ of water ? $\left( K_f =1 \cdot 86\, Kg\, mol ^{-1}\right)$

BITSATBITSAT 2010

Solution:

Let $W g$ of ethylene glycol is added.
The molar mass of ethylene glycol $=62\, g / mol$.
The depression in the freezing point $\Delta T _{ f }= K _{ f } m$
$0.3=1.86 \times \frac{ W }{62\, g / mol \times 5\, kg }$
$W =50\, g$