In hexadecimal system,
$A -10, B -11, C -12, D -13$
Replacing each hexadecimal digit by the corresponding $4$ - digit binary numeral, we have
$(A)_{10}=(1010)_{2},( B )_{10}=(1011)_{2},( C )_{10}=(1100)_{2},( D )_{10}=(1101)_{2}$
$\therefore ( ABCD )_{16}=(1010101111001101)_{2}$