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  4. Considering normal incidence of ray, the equivalent refractive index of combination of two slabs shown in figure is:

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Q. Considering normal incidence of ray, the equivalent refractive index of combination of two slabs shown in figure is:Physics Question Image

ManipalManipal 2005Ray Optics and Optical Instruments

Solution:

The equivalent refractive index of combination of slabs for normal incidence is
$\mu=\frac{\Sigma t_{i}}{\Sigma \frac{t_{i}}{\mu_{i}}}$
In this case, $\mu=\frac{t_{1}+t_{2}}{\frac{t_{1}}{\mu_{1}}+\frac{t_{2}}{\mu_{2}}}$
$=\frac{10+15}{\frac{10}{4 / 3}+\frac{15}{3 / 2}} $
$=\frac{25}{7.5+10}=\frac{25}{17.5} $
$=1.43$