Q. Consider, $y^3+a y^2 x^3+b y x^6-c x^9=0, a, b, c \in R$. If the possible values of $\frac{d^3 y}{d x^3}$ are $-6,12$ and -18 , then
Continuity and Differentiability
Solution:
Correct answer is (a) $a+b=-3$Correct answer is (c) $a + b + c =3$
