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Q. Consider two elements with atomic no. 37 and 53, the bond between their atoms would be

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Solution:

$ 37=1{{s}^{2}},2{{s}^{2}},2{{s}^{6}},3{{s}^{2}}3{{p}^{6}},4{{s}^{2}},3{{d}^{10}},4{{p}^{6}},5{{s}^{1}} $ Thus, the element belongs to IA group and has valency +1. $ 53=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{2}},3{{d}^{10}},4{{p}^{6}},5{{s}^{2}},4{{d}^{10}},5{{p}^{5}} $ Since, there are 7 electrons in the valence shell thus this element requires one electron to complete its octet, ie, has valency -1 Hence, element with atomic number 37 transfers its electron to the element having atomic number 53 and results in the formation of an ionic bond.