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Q. Consider the situation shown in figure. Initially the spring is unstretched when the system is released from rest. Assuming no friction in the pulley, the maximum elongation of the spring isPhysics Question Image

Work, Energy and Power

Solution:

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$\Delta K+\Delta U_{g}+\Delta U_{s}=0$
$0+\left(-m g x_{\max }\right)+\frac{1}{2} k x_{\max }^{2}=0$
$\Rightarrow \frac{1}{2} k x_{\max }^{2}=m g x_{\max }$
$\Rightarrow x_{\max }=\left(\frac{2 m g}{k}\right)$.